A car starts from rest and covers distance of 100m in one second with uniform acceleration.its acceleration is?

Answer 1

To find the acceleration of the car, we can use the kinematic equation for uniformly accelerated motion:

\[ s = ut + \frac{1}{2} a t^2 \]

Where:

• \( s \) is the distance covered (100 m)
• \( u \) is the initial velocity (0 m/s, since the car starts from rest)
• \( a \) is the acceleration (which we need to find)
• \( t \) is the time (1 second)

Since the car starts from rest (\( u = 0 \)), the equation simplifies to:

\[ s = \frac{1}{2} a t^2 \]

Substituting the known values into the equation:

\[ 100 = \frac{1}{2} a (1^2) \]

This simplifies to:

\[ 100 = \frac{1}{2} a \]

To isolate \( a \), multiply both sides by 2:

\[ 200 = a \]

Thus, the acceleration of the car is:

\[ a = 200 , \text{m/s}^2 \]