A car starts from rest and accelerates uniformly along a straight horizontal road at 3 metres second squeared for 4 seconds,after which it continues with a constant velocity for a further 6 seconds.What is the magnitude of the maximum velocity of the car,i.e. The velocity of the car after accelerating for 4 seconds?PLEASE SHOW ALL THE CALCULATIONS
1 answer
V = at = 3m/s^2 * 4s = 12m/s.