A car of mass 1000 kg is on an icy driveway
inclined at an angle of 33◦.
The acceleration of gravity is 9.8 m/s^2
θ
If the incline is frictionless, what is the
acceleration of the car?
2 answers
5.34m/s^2
M*g = 1000 * 9.8 = 9800 N.
Fp = 9800*sin33 = 5337 N. = Force parallel to the incline.
a = Fp/M = 5337/1000 = 5.34 m/s^2.
Fp = 9800*sin33 = 5337 N. = Force parallel to the incline.
a = Fp/M = 5337/1000 = 5.34 m/s^2.