A car moves with a velocity of 72kmh^1 it is brought to rest in 105 find (1)the velocity in ms^1 (2)the iationm show solvings

Answer 1

72 km/hr ( 1 hr/3600s)(1000 m/km) = 20 m/s
assume you want the acceleration in 105 seconds = - 20/105 = - 0.19 m/s^2
but perhaps you mean 105 meters
av speed = 10m/s^2
so time to stop = 105/10 = 10.5 seconds
thenacceleration = -20 m/2 /10.5 s = - 1.9 m/s^2