A car start from rest, moves with uniform acceleration and attains a velocity of 72km/h in 1.5 s it moves with uniform speed for 20 s and is then brought to rest in 10 s under uniform retardation, then total distance travelled using velocity -time graph is?

Question

A car start from rest, moves with uniform acceleration and attains a velocity of 72km/h in 1.5 s it moves with uniform speed for 20 s and is then brought to rest in 10 s under uniform retardation,  then total distance travelled using velocity -time graph is?

ATHUL · Accepted Answer

I ALSO GO THIS GOT AS A QUESTION IN MY EXAM I GOT SOMEWHAT 400 ABOVE AS AN ANSWER

bobpursley · Answer

The area under the velocity-time graph is distance. change 72km/hr to m/s. 72km/hr*1hr/3600s=20m/s area=(20/2)m/s*1.5s +20m/s*20sec +(20/2)*10 check that...

Raghav sharma · Answer

Plz solve the above problem