A car is travelling north on a highway at 25 m/s. Just as the car crosses a perpendicularly intersecting crossroad, the passenger throws out a can horizontally, towards the east. The initial speed of the can relative to the car is 10 m/s. It is released at a height of 1.2 m above the road.

Question

a) What is the initial velocity of the can relative to the road?
b) Where does the can land?

I mainly having trouble figuring the first question. If you could explain it that would be great!

Answer 1

the can is moving 10 m/s from the car
... while the car is moving 25 m/s on the road

add the two vectors to find the can's velocity relative to the road

the can lands north and east of the crossroads
... use the release height to find the flight time

Answer 2

a. Vo = 10 + 25i. = 26.93m/s[68.2o] = Initial velocity.

b. h = 0.5g*t^2 = 1.2,
4.9*t^2 = 1.2,
t = 0.495 s. = Fall time.

d = Vo*t = 26.93[68.2o] * 0.495 = ___m[68.2o]

Answer 3

I got the exact same question (see #6) but with 25 m/s changed to 12.5 m/s and 1.2 m changed to 1.6 m.

You can see the work I showed and swap out the appropriate numbers.

aquantaday.wordpress.com/grade-12-physics-challenge-problems-1-kinematics/