well, 60 km/hr = 16.67 m/s
v(t) = 16.67 - 5.6t
set v=0 and solve for t, then plug that into
s(t) = 16.67t - 2.8t^2
A car is travelling at 60km/h when applies his brakes.If the car decelerates uniformly at 5.6m/s2,how far does the car go after the brakes are applied before coming to rest?
2 answers
200