M*g = Wt. of car.
a. Fn = Mg*Cos17 = 0.956Mg.
Fn/Mg = 0.956Mg/Mg = 0.956.
b. Fn = Mg*Cos30 = 0.866Mg.
Fn/Mg = 0.866Mg/Mg = 0.866.
A car is traveling up a hill that is inclined at an angle θ above the horizontal. Determine the ratio of the magnitude of the normal force to the weight of the car when (a) θ = 17o and (b) θ = 30o.
1 answer
1 answer