Wc = M*g.
Fn = Mg*Cos15.
a. Fn/Wc = Mg*Cos15/Mg = Cos15 = 0.966.
b. Fn/Wc = Mg*Cos32/Mg = Cos32 = 0.848.
A car is traveling up a hill that is inclined at an angle θ above the horizontal. Determine the ratio of the magnitude of the normal force to the weight of the car when (a) θ = 15o and (b) θ = 32o.
2 answers
A car is traveling up a hill that is inclined at an angle θ above the horizontal. Determine the ratio of the magnitude of the normal force to the weight of the car when (a) θ = 16o and (b) θ = 35o.
(a) Ratio = Number
0.96
Units?
(b) Ratio = Number
0.82
Units ?
(a) Ratio = Number
0.96
Units?
(b) Ratio = Number
0.82
Units ?