A car is traveling around a horizontal circular track with radius r = 240 m at a constant speed v = 25 m/s as shown. The angle èA = 34° above the x axis, and the angle èB = 65° below the x axis.
I found the car's acceleration to be 2.6 m/s^2 (a=v^2/r).
Now I need to know the x component of the car's acceleration when it is at point A.
I'm not sure how to go about solving this.
2 answers
whats the answerrrr ?
x-component of car's acceleration:
centripetal acceleration * cos(angle)
remember that centripetal acceleration is v^2/r
centripetal acceleration * cos(angle)
remember that centripetal acceleration is v^2/r
1 answer