What is the speed at t = 0?
When is the speed -8 m/s?
Why are the speeds negative?
a car is moving on straight road with uniform acceleration .the speed of the car varies with time as of-4m/s,2 s-8m/s,so on till 10 seconds. Calculate the distance travelled in 10 seconds.
Asked 30 seconds ago under General Help
4 answers
if we assume that
vₒ = - 4 m/s,
vb = - 8 m/s.
a =?, s = ?
v = vₒ +a•t,
a =(v- vₒ)/t = {-8 –(-4)}/10 = -0.4 m/s².
s= |vₒ|• t+a•t²/2 = 4•10 – 0.4•100/2 = 20 m.
(|vₒ| is the magnitude of initial velocity)
vₒ = - 4 m/s,
vb = - 8 m/s.
a =?, s = ?
v = vₒ +a•t,
a =(v- vₒ)/t = {-8 –(-4)}/10 = -0.4 m/s².
s= |vₒ|• t+a•t²/2 = 4•10 – 0.4•100/2 = 20 m.
(|vₒ| is the magnitude of initial velocity)
since we have -4m/s^2 s-8m/s
it appears that
Vo = -8
a = -4
it appears that
Vo = -8
a = -4
I find it impossible to interpret the problem as written. Take more care to separate sentences with a space and capitalize first words. Exponents must be preceded by ^. Velocity data at a specific time should clearly state the time as well as the velocity