A car is capable of accelerating at a rate of 0.65 m/s2. What is the magnitude of the car’s displacement as it accelerates uniformly from a velocity of 83 km/h to 94 km/h?

Answer 1

∆v = 94 kph - 83 kph = 11 kph
... 11 kph * 1000 m/km / 3600 s/hr = 3.06 m/s

∆t = 3.06 m/s / 0.65 m/s^2 = 4.7 s

average velocity = (83 kph + 94 kph) / 2 = 88.5 kph
... 88.5 kph * 1000 m/km / 3600 s/hr = 24.6 m/s

displacement = ∆t * average velocity