Asked by Angela
A car initially traveling northeast (45° N of E) at 28.3 m/s takes 6.0 s to turn to the east. After the turn, the car is traveling due east at 20.0 m/s. What is the value and direction of the change in velocity?
Answers
Answered by
bobpursley
change in velocity= finalvelocity-initialvelocity
breakthe initial velocity into N,E components.
Vi=28.3*.707N+28.3*.707E
Vf=20 E
subtract. change in velocity=Vf-Vi
breakthe initial velocity into N,E components.
Vi=28.3*.707N+28.3*.707E
Vf=20 E
subtract. change in velocity=Vf-Vi
Answered by
Angela
thank you
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