A car, in overtaking trailer, uniformly accelerated its speed from 40 kph to 90 kph in 8 seconds. Calculate the distance traveled during the period of acceleration.

Answer 1

a = 50kph/8s = 25/4 km/hr/s = 1.736 m/s^2

Vo = 40 km/hr = 11.11 m/s, so

s = Vo*t + a/2 t^2

now just plug in the values for Vo,a,t