average speed during stop = 7.5 m/s
t = 3 meters/7.5 m/s = .4 second
v = 15 + a t
0 = 15 + .4 a
a = -37.5 m/s^2
F = ma = 90(-37.5) = -3375 Newtons
ouch !
A car going 15 m/s is brought to rest in a distance of 3 m as it strikes a pile of dirt. How large a force is exerted by the seatbelts on a 90 kg passenger as the car is stopped?
1 answer