A car is braked so that it slows down with a uniform retardation from 15m/s to 7m/s while it travels a distance of 88m. If a car continues to slow down at the same rate, after what further distance will it be brought to rest?

Answer 1

find a
average speed = (15+7)/2 = 11 m/s
so t = 88/11 = 8 seconds
so
a = (7-15)/8 = - 1 m/s^2

v = Vi + a t
0 = 7 - 1 t
t = 7 during final stop

d = Vi t + (1/2) a t^2
d = 7*7 - (1/2)49
d = 49/2 = 24.5 meters

Answer 2

A car travelling with a speed of 15m/s is braked and it slows down with uniform retardation.It covers of 88 m as its velocity reduces to 7m/s.If the car continues to slow down with the same ratr,further distance will it be brought to rest?