A car drives down a road in such a way that its velocity (in m/s) at time t (seconds) is v(t)=3(t^(1/2))+4. Find the car's average velocity (in m/s) between t=4 and t=6.

Answer 1

find out how far it went between t = 4 and t = 6, then divide by 2

int [ 3 t^.5]dt + int [4]dt t=4 to t=6

3(2/3)t^3/2 + 4t

2 t^3/2 + 4 t

at t = 6 , 2 sqrt(6^3) + 24=
6sqrt6+24
=38.7

at t = 4, 2 sqrt(4^3) + 16=
2*8 + 16 = 32

38.7 - 32

then divide by two seconds to find average m/s

Answer 2

(38.7-32)/2=3.35

It's not the correct answer.