average value of f(x) over the interval [a,b] is
∫[a..b] f(x) dx
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(b-a)
You did the integral, but did not divide by 3
A car drives down a road in such a way that its velocity (in m/s) at time t (seconds) is v(t)=2t^(1/2)+3.
Find the car's average velocity (in m/s) between t=5 and t=8.
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So I used integrals for this and put ∫2t^(1/2)+3 and got 4/3(t^(3/2))+3t.
Then I substituted in 8 and 5 into that and subtracted that, but it's still marked wrong? I even entered it into Symbolab to check but that was also incorrect.
(I got ((64√2 - 20√5)/3)+9 from symbolab)
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