the vertical speed is 200 sin30 = 100 m/s
So, the height is
h(t) = 100t - 4.9t^2
As you recall from algebra I, the vertex of the parabola is at t = -b/2a, which in this case is 100/9.8
So, plug that in to get the max height.
The ball is in the air twice that long, and you know the horizontal speed is 200 cos30, so just multiply speed*time to get distance.
A cannon is fired from the ground at an angle of 30 degrees. It is being shot an an initial velocity of 200m/s. What is the maximum height of the cannon ball? How fat will the cannon ball travel before it hits the ground
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what is the answer to my question?
A canon was fired with a muzzle velocity of 100 m/s, mounted at an angle of 30 degrees above the ground.
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