When fired straight up, the height attained is
H = V^2/(2g)
When fired at at angle A, the range is
R = (V^2/g)sin(2A)
When the angle is 45 degrees, R = V^2/g
and R = 2 H. (The H refers to the straight-up value)
Therefore the answer is 400 m.
A projectile fired vertically up from a cannon rises 200 m before returning to the ground. If the same cannon were to fire the same projectile at an angle 45 degrees, then the maximum range would be m.
2 answers
A car is traveling along a straight road increases its speed from 30.0 m/s to 50.0 m/s in a distance of 180 m. If the acceleration is constant, how much time elapses while the car moves this distance?
1 answer