Asked by yelya
A cannon barrel is elevated at an angle of 45°. It fires a ball with a speed of 350 m/s. (For the following questions, ignore air resistance.)
(a) What height does the ball reach?
(b) How long is the ball in the air?
(c) What is the horizontal range of the cannon?
(a) What height does the ball reach?
(b) How long is the ball in the air?
(c) What is the horizontal range of the cannon?
Answers
Answered by
drwls
a) Solve for V:
(sin45*V)^2^2/2 = (1/4)*V^2 = g H
b ) 2*V sin 45/g
c) 2 sin 45 cos 45 V^2/9 = V^2/g
(sin45*V)^2^2/2 = (1/4)*V^2 = g H
b ) 2*V sin 45/g
c) 2 sin 45 cos 45 V^2/9 = V^2/g
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