Asked by yelya

A cannon barrel is elevated at an angle of 45°. It fires a ball with a speed of 350 m/s
What is the horizontal range of the cannon?

Answers

Answered by drwls
V^2/g, at that elevation angle.
Answered by Anonymous
[2(350^2)cos45sin45]/g = 12.49 m
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions