A candy store makes a 9-pound mixture of gummy candy, jelly beans, and hard candy. The cost of gummy candy is $2.00 per pound, jelly beans cost $3.00 per pound, and hard candy costs $3.00 per pound. The mixture calls for two times as many gummy candy pieces as jelly beans. The total cost of the mixture is $23.00. How much of each ingredient did the store use?%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0A3 lbs. gummy candy, 2 lbs. jelly beans, 4 lbs. hard candy%0D%0A3 lbs. gummy candy, 2 lbs. jelly beans, 4 lbs. hard candy%0D%0A%0D%0A4 lbs. gummy candy, 2 lbs. jelly beans, 3 lbs. hard candy%0D%0A4 lbs. gummy candy, 2 lbs. jelly beans, 3 lbs. hard candy%0D%0A%0D%0A4 lbs. gummy candy, 3 lbs. jelly beans, 2 lbs. hard candy%0D%0A4 lbs. gummy candy, 3 lbs. jelly beans, 2 lbs. hard candy%0D%0A%0D%0A2 lbs. gummy candy, 3 lbs. jelly beans, 4 lbs. hard candy%0D%0A2 lbs. gummy candy, 3 lbs. jelly beans, 4 lbs. hard candy
1 answer
We are given that the total weight of the mixture is 9 pounds:
G + J + H = 9 (equation 1)
We are also given that the cost of gummy candy is $2.00 per pound, the cost of jelly beans is $3.00 per pound, and the cost of hard candy is $3.00 per pound. The total cost of the mixture is $23.00:
2G + 3J + 3H = 23 (equation 2)
The mixture calls for two times as many gummy candy pieces as jelly beans:
G = 2J (equation 3)
We can solve this system of equations to determine the values of G, J, and H.
From equation 3, we can substitute G = 2J into equation 1 and simplify:
2J + J + H = 9
3J + H = 9 (equation 4)
Now we have a system of two equations with two variables (equations 2 and 4). We can solve this system using substitution or elimination method.
Let's solve it using the substitution method:
From equation 4, we can solve for H:
H = 9 - 3J
Substitute this value of H into equation 2:
2G + 3J + 3(9 - 3J) = 23
2G + 3J + 27 - 9J = 23
2G - 6J = -4
G - 3J = -2 (equation 5)
Now we have a system of two equations with two variables (equations 3 and 5).
Substituting G = 2J from equation 3 into equation 5:
2J - 3J = -2
-J = -2
J = 2
Substitute this value of J into equation 3 to solve for G:
G = 2J
G = 2(2)
G = 4
Now substitute the values of G and J into equation 4 to solve for H:
3J + H = 9
3(2) + H = 9
6 + H = 9
H = 9 - 6
H = 3
So, the solution is G = 4, J = 2, and H = 3.
Therefore, the candy store used 4 pounds of gummy candy, 2 pounds of jelly beans, and 3 pounds of hard candy.