A cable lifts a 1370 kg elevator at a constant velocity for a distance of 42 m. What is the work done by each of the following?

Question

(a) the tension in the cable (J)

(b) the elevator's weight (J)

work by tension in cable if the car is not accelerating=mgh

workweight=-mgh

This assumes the elevator was moving initially, if it was stopped then one has to add the final KE the elevator has. THe problem is poorly written in that regard.

Answer 1

a) 411,600

b) -42000

I need help!

Answer 2

I do not Know :(