fell 40 m
v then is
Vi =sqrt(2gh)= sqrt(2*9.81*40)
= 28 m/s
so in the 12 m he slows from
28 to 8 m/s
average speed = (28+8)/2 =36/2 = 18m/s
t = 12 / 18 = 2/3 second
average total force = change in momentum/time
= 55 * 20 *3/2 = 550*3 = 1650 but
add the weight which the bunge also supplies
1650 + m g = 1650+55*9.81
= 2190 N
A bungee jumper runs off a platform and falls 40m before his bungee cord begins to stretch. Once the bungee cord begins to stretch his velocity slows by 20 m/s in 12m. If the mass of the bungee jumper is 55kg, what is the average force the bungee applies on him?
1 answer
1 answer