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A bullet of mass 8 g strikes a ballistic pendulum of mass 2.0 kg. The center of mass of the pendulum rises a vertical distance...Asked by danny
A bullet of mass 13 g strikes a ballistic pendulum of mass 1.7 kg. The center of mass of the pendulum rises a vertical distance of 11 cm. Assuming that the bullet remains embedded in the pendulum, calculate the bullet’s initial speed. Round your answer off to one place after the decimal.
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Answered by
oobleck
the PE at the top of the swing is mgh = (1.7+0.013)*9.81*0.11 = 1.848J
so, that must have been equal to the bullet's KE: 1/2 mv^2 = 1.848
so, that must have been equal to the bullet's KE: 1/2 mv^2 = 1.848
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