A bullet of mass 1.8 X 10-3 kg is moving at +500. m/s when it impacts a tree stump. It penetrates into the stump 6.00 centimeters before coming to rest.

1. Assuming the acceleration to be constant, calculate the force (including direction) exerted by the stump on the bullet.

1 answer

Vf^2=Vi^2+2ad

but a= Force/mass

solve for force.