Answer:
423m/s
Explanation:
Suppose after the impact, the bullet-block system swings upward a vertical distance of 0.4 m. That's means their kinetic energy is converted to potential energy:
where m is the total mass and h is the vertical distance traveled, v is the velocity right after the impact at, which we can solve by divide both sides my m
Let g = 9.81 m/s2
According the law of momentum conservation, momentum before and after the impact must be the same
where are the mass and velocity of the bullet before the impact, respectively. are the mass and velocity of the block before the impact, respectively, which is 0 because the block was stationary before the impact
as shown in the figure a bullet of mass 0.010 kg moving horizontally suddenly strikes a block of wood of mass 1.5 kg that is suspended as a pendulum. The bullet lodges in the wood, and together they swing upward a vertical distance of 0.40 m. The length of the string is 2.0 m. What was the speed of the bullet just before it struck the wooden block?
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