momentum after=momentum before
momentum before=Mbullet*Vbullet
Momentum after=(.49+.01)10=Mb*Vb
solve for Vbullet
A bullet of mass 0.01kg Is fired into a sandbag of mass 0.49kg hanging from a tree. The sandbag, with the bullet embedded into it, swings away at 10m/s.find
a)the momentum after collision
b)the momentum before collision
c)the velocity of the bullet.
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Yes
THE MOMENTUM BEFORE THE COLLISION
102m/s
a)0.5 b)0.5 c)102m/s
e sandbag,with the bullet embedded into it,swings away at 10 meter per second
A boy of mass 40 kg jumps from a wall at 4 m/s. He kneels and stands in 1 second. Calculate the force required to slow it down. How can this force be different if he bends his knee and does not stop in 0.1 second? from given
given m=40Kg, v 4 m/s ,t1=1s ,t2= 0.1s
solution F= ma ,40Kg*4m/s/0.1s
160m/s/0.1s
1600m/s2
solution F= ma ,40Kg*4m/s/0.1s
160m/s/0.1s
1600m/s2
11 answers