a. (.01+.49)10
b. same as a.
c. .01V=momentum in b.
a bullet of mass 0.01kg is fired into a sandbag of mass 0.49kg handing from atree.the sandbag with the bullet embedded into it swing away at 10m/s find: a.the momentum after collision b.the momentum before the collision c.the velocity of the bullet
11 answers
A=5 b=5 c= 0.01
A)Pf=(m1+m2)v
= (0.01+0.49)10
=5 Kgm/s
B)Po=Pf so it's the same as the first one.
C)v=0.05
= (0.01+0.49)10
=5 Kgm/s
B)Po=Pf so it's the same as the first one.
C)v=0.05
by what angle velocity will be 0.05m/s?
0.01v=5kgm/s is 500m/s
I hate it u didn't even give me good answers just stupid ones and no explanation
you're good but can you make it brief abt the sol
anyway thank you for your help
anyway thank you for your help
A.5
B.5
C.,500
B.5
C.,500
A.5
B.5
C.500
B.5
C.500
A.5
B.5
C.500
B.5
C.500
Mohammed