A bullet of 0.06kg travelling at 120m/s penetrates into a fixed target and is brought to rest in 0.01s. The distance through which it penetrates is:

Question

A bullet of 0.06kg travelling at 120m/s  penetrates into a fixed target and is brought to rest in 0.01s. The distance through which it penetrates is:
Answer is 60cm

R_Scott · Accepted Answer

average velocity = (initial + final) / 2 = (120 + 0) / 2 = 60 m/s distance = velocity * time = 60 m/s * 0.01 s

vickky · Answer

Tnx a lot I am grateful