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A bullet is fired from a gun at 300 m/s. It hits the ground at 3s later. At what angle (in degrees) above the horizon was the bullet fired? (Assume no air resistance)

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The time of the projectile motion is
t=2v₀sinα/g

sinα=gt/2v₀ =9.8•3/2•300=0.05
α=arcsin0.05=2.8°

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