3. A bullet is fired from at a shooting range. The bullet hits the ground after 0.32 seconds. How far did it travel horizontally and vertically in this time if it was fired at a velocity of 1100 m/s?

Answer 1

For the horizontal:
x = vo,x * t
where
x = horizontal distance
vo,x = initial horizontal velocity
t = time

x = 1100 m/s * 0.32 s
x = 352 m

For the vertical:
h = vo,y * t - (1/2)gt^2
where
h = height
vo,y = initial vertical velocity (which is zero)
g = acceleration due to gravity = 9.8 m/s^2

h = 0 - (1/2)(-9.8)(0.32^2)
h = 0.502 m

hope this helps~ `u`