A buffer is prepared by mixing 205 mL of .452 M HCl and .500 L of .400 M sodium acetate. Ka =1.80 x 10^-5
I got the pH is 4.79 but i can't figure out the grams of KOH
the problem says how many grams of KOH must be added to .500 L of the buffer to change the pH by .125 units?
I got .221 g KOH but it says that's wrong
1 answer
I worked this yesterday. Let me see if I can find it.
1 answer