deltaL= L (1+alpha*30)
70.5-L=L(1+alpha*30)
solve for L
A brass measuring tape is correct at 20 degree Celsius. The value obtained when the length of a field is measured with the rule at 50 degree Celsius appears to be 70.5m. what is the true length of the field Linear expansivity of brass =1.8 ×10 raise to power minus five per Kelvin.
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L²=L¹(1+a[∅]) FORMULA
70.5(1+1.8×10^-5[20-60])=70.46m
70.5(1+1.8×10^-5[20-60])=70.46m
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70.46m