sinA = 1m/3m = 0.333. A = 19.5o.
Fp = Mg*sinA = 600*sin19.5 = 200 N. = Force parallel with plane.
Fs = Force of static or starting friction.
Fe-Fp-Fs = M*a.
400-200-Fs = M*0 = 0,
Fs = 200 N.
A boy uses a rope to haul a box of weight 600N up an inclined wooden plane of effective length 3.0m and onto a platform 1.0m high. If in doing so, he exerts a force of 400N on the rope. Draw the diagram of all the forces acting on the box and calculate the frictional force between the box and the incline plane
2 answers
correct
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