A boy sitting on the edge of a vertical cliff fires a rock with a slingshot at a velocity of 16.45758956 m/s and an angle of 59.78 degrees above the horizontal.

Question

A boy sitting on the edge of a vertical cliff fires a rock with a slingshot at a velocity of 16.45758956 m/s and an angle of 59.78 degrees above the horizontal.
The rock lands in a lake at the base of the cliff, a horizontal distance of 89.67 meters beyond the base of the cliff. How high is the cliff in meters?

Please explain steps and how to get there. please Thank you!!!

bobpursley · Answer

break the initial velocity into vertical and horizontal components with the sine and cosine.

horizontal distance=vihorz*time
solve for time in air.

in the vertical:
hfinal-hinitial= vivert*time-4.9t^2
solve for hfinal-hinitial.

projectile motion · Answer

i got an answer of y=-420.2599461m is this right??