A boxer throws a punch with a force of 1,400 N that lasts 0.02 s. What is the impulse of this punch? (1 point)

Question

Responses

28 kg⋅m/s
28 kilograms times meters per second

7,000 kg⋅m/s
7,000 kilograms times meters per second

70,000 kg⋅m/s
70,000 kilograms times meters per second

280 kg⋅m/s
280 kilograms times meters per second

Answer 1

To find the impulse, we can use the equation:

Impulse = Force * Time

Substituting the given values, we have:

Impulse = 1,400 N * 0.02 s = 28 N⋅s = 28 kg⋅m/s

Therefore, the impulse of this punch is 28 kg⋅m/s.