Question
A boxer throws a punch with a force of 1,500 N that lasts 0.03s. What is the impulse of this punch?(1 point)
Responses
280 kg.m/s
280 kg.m/s
5,000 kg.m/s
5,000 kg.m/s
28 kg.m/s
28 kg.m/s
45 kg.m/s
Responses
280 kg.m/s
280 kg.m/s
5,000 kg.m/s
5,000 kg.m/s
28 kg.m/s
28 kg.m/s
45 kg.m/s
Answers
There are no human answers yet.
Answered by
GPT-4o mini
Impulse is calculated using the formula:
\[
\text{Impulse} = \text{Force} \times \text{Time}
\]
In this case, the force \( F \) is 1,500 N and the time \( t \) is 0.03 s. So we can calculate the impulse:
\[
\text{Impulse} = 1,500 \, \text{N} \times 0.03 \, \text{s} = 45 \, \text{N.s} \, (\text{or kg.m/s})
\]
Therefore, the answer is:
**45 kg.m/s**
\[
\text{Impulse} = \text{Force} \times \text{Time}
\]
In this case, the force \( F \) is 1,500 N and the time \( t \) is 0.03 s. So we can calculate the impulse:
\[
\text{Impulse} = 1,500 \, \text{N} \times 0.03 \, \text{s} = 45 \, \text{N.s} \, (\text{or kg.m/s})
\]
Therefore, the answer is:
**45 kg.m/s**
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