A box which has a mass of 32.8kg is placed on a plane which is inclined at 40.0° above the horizontal. The sliding friction force acting between the box and the plane is 36.4N. What is the acceleration of the box as it slides down the plane?

Answer 1

weight component down slope = 32.8*9.81*sin 40
net force in direction of motion = 32.8*9.81*sin 40 - 36.4
a = F/m = net force /32.8