speedbottom:
KE at bottom=PE at top
1/2 mv^2=mgh
v^2=2gh=2*9.8*2
speedbottom=sqrt(4*9.8) m/s
A block of ice of mass 30 kg is at rest atop an inclined plane of vertical height
2 m. It is released and slides down the inclined plane. What is its speed at the bottom of the inclined plane?
2 answers
a
d
d
d
c
c
a
d
d
d
c
c
a
2 answers