Ask a New Question

A box slides down a 33° ramp with an acceleration of 1.38 m/s2. Determine the coefficient of kinetic friction between the box and the ramp.

1 answer

Component of force along the plane (downward), F
= mgsin(θ)

Let frictional force be ff, then
ff=μmgcos(θ)

Net acceleration
(F-ff)/m = 1.38 m/s²

Solve for μ

Ask a New Question or answer this question.

Similar Questions

A 475 gram box is given a push and it then slides up and back down a ramp with a 35.0° incline. The coefficient of friction is
1. 0 answers
A box slides down a 33.3◦ ramp with an acceleration of 1.07 m/s 2 . The acceleration of gravity is 9.8 m/s 2 . Determine the
1. 2 answers
A box slides down a 27.7° ramp with anacceleration of 1.25 m/s². The acceleration of gravity is 9.8 m/s². Determine the
1. 2 answers
A box slides down a 36° ramp with an acceleration of 1.05 m/s2. Determine the coefficient of kinetic friction between the box
1. 0 answers

more similar questions