A box slides down a 27.7° ramp with an

Question

acceleration of 1.25 m/s².
The acceleration of gravity is 9.8 m/s².

Determine the coefficient of kinetic friction between the box and the ramp.

Answer 1

normal force = m g cos 27.7
friction force up slope = mu m g cos 27.7

gravity component down slope = m g sin 27.7

so
m (1.25) = m g sin 27.7 - mu m g cos 27.7

mu g cos 27.7 = g sin 27.7 - 1.25
solve for mu

Answer 2

Thank you