normal force = m g cos 30
friction force up ramp = mu m g cos 30
gravity force component down ramp = m g sin 30
so
m g sin 30 - mu m g cos 30 = m (1.25)
mu = (g sin 30 - 1.25)/(g cos 30)
A box slides down a 30.0 degree ramp with an acceleration of 1.25m/s². Determine the coefficient of Kinetic friction between the box and the ramp.
I'm not sure to work it out I draw a picture to see if it would help me but I'm still stuck..
1 answer