a box of mass 5.7 kg slides across a floor and comes to a complete stop. if its initial speed was 10km/h and mu = 0.34 find the acceleration of the box

Answer 1

F=ma
-mu*mg=ma
solve for a

Answer 2

-3.33m/s2

Answer 3

-Ffr=ma (because it is decelarating, therefore a=negative)
-19=5.7a
-19/5.7=a
a= -3.33m/s2