A box of mass 12.6 kg is pulled to the right with a horizontal force of 14 N. If the box moves to the right with a constant velocity of 1.68 m/s, what is the frictional force acting on the box? What is the coefficient of friction for this situation?
3 answers
Since there is no accleration, 14 N is the friction force. The speed does not matter at all. The coefficioent of friction is 14 N divided by the weight, M g.
The driver of a 1024 kg truck traveling 32.6 m/s North on I-77 has to make a sudden stop. If it requires a distance of 57.1 m for the truck to stop, use conservation of energy to find the net force acting on the truck.
Cory's question was posted and answered later, in a separate thread
1 answer