Consider the box being pulled across the horizontal surface again. If the box has a mass of 10kg, the coefficient of friction is 0.25,the distance that the box is pulled is 5m, the force is 150N and the angle is 30 degrees, ehat was the initial speed of the box if the final speed is 12m/sec ?

Answer 1

Initial energy + work putin=finalenergy+friction

1/2 m vi^2 + 150*cos30*5=1/2 m 12^2 + .25(10g+150sin30)10

solve for vi