A box moves down a conveyor belt the is angled at 15 degrees, at a rate of 6m/s. The box then enters a dump off that is 3m below the end of the belt, what is the horizontal distance between the dump off and the belt?

Question

I have no idea where to start with this...I know you have x and y components of something but I don't know what to do...any help in the right direction would be appreciated.

Answer 1

:You have to figure the time it took to fall 3m. It had an initial vertical velocity downward of -6sin15.

h=vi*t -4.9t^2
solve for t.

Then, you know the intial horizontal velocity is 6cos15, and the time, so what distance did it travel horizontally?

Answer 2

You can't solve for t from that though can you? If you use quadratic equation its a negative sign under the root and you can't take the root of that. I'm confused:S