Asked by Iklishi
A 11.5 m long conveyor belt, inclined at 30.0°, is used to transport bundles of newspapers from the mailroom up to the cargo bay to be loaded on to delivery trucks. Each newspaper has a mass of 1.0 kg, and there are 21 newspapers per bundle. Determine the power that the conveyor develops if it delivers 15 bundles per minute.
Answers
Answered by
Damon
How far do we lift this?
11.5 sin 30 = 5.75
mass of a bundle = 1 * 21 = 21 kg
increase of potential energy of bundle = m g h = 21 * 9.8 * 5.75 = 1183 Joules
so we do 1183 Joules * 15 lifts in 60 seconds = 296 watts
Now it is not clear to me from the question if the newspapers are already moving when they hit the belt (like from a horizontal belt) If not, they must also be given kinetic energy by the belt.
Therefore that is the best I can do for you.
11.5 sin 30 = 5.75
mass of a bundle = 1 * 21 = 21 kg
increase of potential energy of bundle = m g h = 21 * 9.8 * 5.75 = 1183 Joules
so we do 1183 Joules * 15 lifts in 60 seconds = 296 watts
Now it is not clear to me from the question if the newspapers are already moving when they hit the belt (like from a horizontal belt) If not, they must also be given kinetic energy by the belt.
Therefore that is the best I can do for you.
Answered by
Iklishi
It's the best that I need. I appreciate the help! :)
Answered by
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