A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is 0.15 and the push imparts an initial speed of 3.9 m/s?

Answer 1

Acceleration, a = -μg
initial velocity, v0 = 3.9 m/s
final velocity, v = 0 m/s
Using
2aS=v²-v0², where
Distance to stop, S = (v²-v0²)/(2a)

Answer 2

300